Answer:
A. 130J / kg°C
Step-by-step explanation:
Amount of heat (Q) = 5200 J
mass (m) = 2 kg
temperature (dt) = 20°C
specific heat capacity (S) = ?
We know
Q = msdt
5200 = 2 * s * 20
s = 5200 / 40
s = 130 J /kg °C
Hope it will help :)
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