Question

If a radiographer stands 1 m from an x-ray tube and is subjected to an exposure rate dose of 4 mGya per hour, what will be the exposure rate if the same radiographer moves to a position 2 m from the x-ray tube?

Answer 1

The exposure rate would decrease to 1 mGya per hour when the radiographer moves from 1 m to 2 m away from the x-ray tube due to the inverse square law of radiation.

Step-by-step explanation:

When the radiographer moves from 1 m to 2 m away from an x-ray tube, the exposure rate dose will follow the inverse square law of radiation. This law states that the intensity of radiation is inversely proportional to the square of the distance from the source. If the exposure dose is 4 mGya per hour at 1 m, moving to 2 m would increase the distance by a factor of two, and the exposure dose would decrease by the square of that factor. Therefore, the exposure rate at 2 m would be 1 mGya per hour (4 mGya divided by 2 squared, which is 4).

To determine the new exposure rate, we can use the inverse square law for radiation. The inverse square law states that the intensity of radiation is inversely proportional to the square of the distance from the source. In this case, since the radiographer moves from 1 m to 2 m, the distance doubles. Therefore, the exposure rate will be one-fourth (1/2^2) of the original exposure rate.

So, if the original exposure rate was 4 mGya per hour, the new exposure rate will be 1 mGya per hour when the radiographer moves to a position 2 m from the x-ray tube.