Question

A spring with k = 33.5 N/m has a

1.20 kg mass attached. It is pulled
0.120 m and released. How much
mechanical energy does it have?
(Unit = J)

Answer 1

M.E = 0.241 Joules.

Step-by-step explanation:

Given the following data;

Spring constant, k = 33.5 N/m

Extension, e = 0.12m

Mass = 1.20kg

To find the mechanical energy (M.E);

Mathematically, mechanical energy is given by this formula;

M.E = ½ke²

Where;

• k is the constant of elasticity (spring constant).
• e is the extension of the string.

Substituting into the equation, we have;

M.E = ½*33.5*0.12²

M.E = ½*33.5*0.0144

M.E = 0.4824/2

M.E = 0.241 Joules.