4.5k views
0 votes
When performing magnification radiography, if the Source-to-Image Distance (SID) is 40" and the Object-Image Receptor Distance (OID) is 6", what is the magnification of the object?

User Rejj
by
7.8k points

1 Answer

0 votes

Final answer:

In magnification radiography with an SID of 40 inches and an OID of 6 inches, the magnification of the object is approximately 1.18 times.

Step-by-step explanation:

When performing magnification radiography, the magnification (M) of the object can be determined using the formula: M = SID / (SID - OID). In this case, the Source-to-Image Distance (SID) is 40 inches, and the Object-Image Receptor Distance (OID) is 6 inches. By substituting these values into the formula, we get M = 40 / (40 - 6) = 40 / 34. Hence, the magnification of the object is approximately 1.18 times.

To calculate the magnification of an object in magnification radiography, you can use the formula:

Magnification = SID / OID

where SID represents the Source-to-Image Distance and OID represents the Object-Image Receptor Distance.

In the given scenario, the SID is 40" and the OID is 6". Plugging these values into the formula, we get:

Magnification = 40" / 6" = 6.67

Therefore, the magnification of the object is 6.67.

User Lisaann
by
7.5k points