Final answer:
The molar mass of Copper Sulfate Pentahydrate, CuSO4·5H2O, is calculated by adding the molar masses of the individual atoms constituting the compound, resulting in 329.72 g/mol.
Step-by-step explanation:
To calculate the molar mass of Copper Sulfate Pentahydrate (CuSO4·5H2O), we need to sum the molar masses of each element and the water molecules associated with it.
The molar masses for copper (Cu), sulfur (S), oxygen (O), and hydrogen (H) are 63.55 g/mol, 32.07 g/mol, 16.00 g/mol, and 1.01 g/mol respectively. A single unit of copper sulfate consists of one copper atom, one sulfur atom and four oxygen atoms, and the pentahydrate contains five additional water molecules.
The molar mass calculation is as follows:
Cu: 1 × 63.55 g/mol = 63.55 g/mol
S: 1 × 32.07 g/mol = 32.07 g/mol
O: 4 (in CuSO4) + 5 × 2 (in 5H2O) = 14 × 16.00 g/mol
= 224.00 g/mol
H: 5 × 2 × 1.01 g/mol = 10.10 g/mol
Adding them together, the molar mass of Copper Sulfate Pentahydrate is:
63.55 g/mol (Cu) + 32.07 g/mol (S) + 224.00 g/mol (O) + 10.10 g/mol (H) = 329.72 g/mol.