Answer:
There will be 132 seats in row 25
Explanation:
1st term = 12
common difference = 5
f(x) = 12 + 5(x - 1)
f(25) = 12 + 5(25-1)
f(25) = 12 + 5(24)
f(25)= 12+120
f(25)=132
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