Final answer:
Using the given data, we find that the 95% confidence interval for the mean savings is $60.82 to $78.48 per visit.
Step-by-step explanation:
To construct a 95% confidence interval for the mean savings for a televisit to the doctor as opposed to an office visit, we can use the formula:
CI = X-bar ± (t-value) * (s/√n)
Where X-bar is the sample mean, t-value is the critical value from the t-distribution table, s is the sample standard deviation, and n is the sample size.
Using the given data, we find that the mean savings (X-bar) is $69.65, the sample standard deviation (s) is $20.67, and the sample size (n) is 20. The t-value for a 95% confidence interval with 19 degrees of freedom is approximately 2.093.
Plugging these values into the formula, we get:
CI = $69.65 ± (2.093) * ($20.67/√20)
CI = $69.65 ± $8.83
Therefore, the 95% confidence interval for the mean savings for a televisit to the doctor as opposed to an office visit is $60.82 to $78.48 per visit.