Answer:
Explanation:
7th term of the first sequence is 14
first we need to find out the nth term so,
tn=Ti+(n-1)d
2(n-1)2
2+2n-2
2n+2-2
2n+0
Now we need to find out the 7th term
n=7
2(7)-0
14-0=0
Second sequences 7th term is 33
first we need to find the nth term
1(n-1)3
1+3n-3
3n+1-3
3n-2
so now we need to find 7th term
3(7)-2
35-3
33
the 4th sequence 7th term is 20