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7 votes
7 votes
A worker drives to work each morning, always leaving at the same time. When he drives at

an average speed of 30km/hr he arrives six minutes early, but when he drives at an average
speed of 20km/hr he arrives six minutes late. What is the distance between his house and his
office? Calculate his average speed when he arrives precisely on time. Explain your answer.

User Alexey  Usharovski
by
2.4k points

1 Answer

21 votes
21 votes

Step-by-step explanation:

speed = distance/time

distance/speed = distance / distance/time = time

when we define the equations, we must be careful to use the same scales as in the given numbers.

as we are dealing with km/h for speed, we need to have distance measured in km, and time in hours.

6 minutes is therefore 1/10 of an hour (1 hour = 60 minutes).

distance/30 = x - 1/10

distance/20 = x + 1/10

we subtract equation 2 from equation 1 :

distance/30 = x - 1/10

- distance/20 = x + 1/10

-----------------------------------

distance/30 - distance/20 = -2/10

we multiply by 60 to eliminate all fractions :

2×distance - 3×distance = -2×6 = -12

-distance = -12

distance = 12 km

x = the travel time to arrive on time.

distance/30 = x - 1/10

12/30 = x - 1/10

12 = 30x - 3

15 = 30x

x = 15/30 = 0.5 hours = 30 minutes

so, he has half an hour for his 12 km trip to work to arrive precisely on time.

that means his average speed for that must be

12/0.5 = 24/1 = 24 km/h

User Mitra Razmara
by
2.8k points