Final answer:
A single photon of yellow light with energy 3.15 x 10^-19 Joules cannot remove an electron from Aluminum because its energy is less than Aluminum's work function (6.53689 x 10^-19 Joules).
Step-by-step explanation:
To determine whether a single photon of yellow light with energy E = 3.15 x 10-19 Joules will be able to remove an electron from Aluminum, we must compare the photon's energy to the work function of Aluminum. The work function is the minimum energy required to remove an electron from the surface of a material.
The work function of Aluminum is given as 4.08 eV. Since 1 eV is equal to 1.60218×10-19 J, we convert the work function to Joules: 4.08 eV × 1.60218×10-19 J/eV = 6.53689×10-19 J.
Comparing the photon's energy (3.15 x 10-19 J) to the work function (6.53689 x 10-19 J), the photon's energy is less than the work function. Therefore, a single photon of yellow light cannot remove an electron from Aluminum because its energy is insufficient to overcome the work function.