Answer: C
l
2
→
H
C
l
O
C
l
2
→
2
H
C
l
O
(Cl balance)
C
l
2
+
2
H
2
O
→
2
H
C
l
O
(O balance)
C
l
2
+
2
H
2
O
→
2
H
C
l
O
+
2
H
+
(H balance)
C
l
2
+
2
H
2
O
→
2
H
C
l
O
+
2
H
+
+
2
e
−
(Charge balance)
C
l
2
+
2
H
2
O
→
2
H
C
l
O
+
2
H
+
+
2
e
−
balanced half-reaction)
Step-by-step explanation: