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4 votes
This compiles:
char letter = "hello".substring(0, 0);
a) True
b) False

User Yemy
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1 Answer

4 votes

Final answer:

The statement 'char letter = "hello".substring(0, 0);' will not compile because the substring method returns a String, not a char, and in this case, it would return an empty string. The correct answer is:b) False

Step-by-step explanation:

The content loaded question posed was: "This compiles: char letter = "hello".substring(0, 0); a) True b) False". The answer to this question is b) False. The reason it does not compile is that the substring method in Java returns a String and not a char type. Furthermore, the specific substring method "hello".substring(0, 0) would return an empty string, not a single character. The provided code char letter = "hello".substring(0, 0); would not compile in Java because of a type mismatch. The substring method returns a String, but you are trying to assign it to a char variable (letter). In Java, you cannot directly assign a String to a char variable without explicit conversion. The correct answer is: b) False To fix this, you could either change the type of the letter variable to String or modify the code to extract a single character from the substring, such as char letter = "hello".charAt(0);.

User Ibrewster
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