172k views
3 votes
The multiplicative inverse of 8 and 8h - 40

User Ghpguru
by
6.5k points

1 Answer

8 votes

Answer:

1) The multiplicative inverse of
8 is
(1)/(8).

2) The multiplicative inverse of
8\cdot h - 40 is
(1)/(8\cdot h - 40).

Explanation:

Mathematically, let
w and
v real numbers.
w is the multiplicative inverse if and only if
v\cdot w = 1. Now we proceed to determine the multiplicative inverse of each number:

1)
v = 8

(i)
v\cdot w = 1 Definition of multiplicative inverse

(ii)
v = 8 Given

(iii)
8\cdot w = 1 (ii) in (i)

(iv)
w\cdot (8\cdot 8^(-1)) = 8^(-1)\cdot 1 Compatibility with multiplication/Associative and commutative properties

(v)
w = 8^(-1) Existence of multiplicative inverse/Modulative property

(vi)
w = (1)/(8) Definition of division/Result

The multiplicative inverse of
8 is
(1)/(8).

2)
v = 8\cdot h - 40

(i)
v\cdot w = 1 Definition of multiplicative inverse

(ii)
v = 8\cdot h - 40 Given

(iii)
(8\cdot h - 40)\cdot w = 1 (ii) in (i)

(iv)
w\cdot [(8\cdot h - 40)\cdot (8\cdot h-40)^(-1)] = (8\cdot h - 40)^(-1)\cdot 1 Compatibility with multiplication/Associative and commutative properties

(v)
w = (8\cdot h-40)^(-1) Existence of multiplicative inverse/Modulative property

(vi)
w = (1)/(8\cdot h-40) Definition of division/Result

The multiplicative inverse of
8\cdot h - 40 is
(1)/(8\cdot h - 40).

User WhatsTheDiff
by
6.3k points