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3- Given 90.0 g C6H1206 a- How many moles of Glucose are present in 90.0 g of glucose?
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3- Given 90.0 g C6H1206
a- How many moles of Glucose are present in 90.0 g of glucose?

User Earl Ferguson
by
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1 Answer

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molar mass = 180.18

//


90.0 \: g * (1 \: mol)/(180.18 \: g) = 0.4995004995 \: mol


= 0.500 \: mol

User Teerasej
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