Question

If log3. 18+log3. 3-log3. x=3​

Answer 1

-1.631

Explanation:

Got the answer on edge

Answer 2

Given:

The equation is

`\log_318+\log_33-\log_3x=3`

To find:

The solution for the given equation.

Solution:

We have,

`\log_318+\log_33-\log_3x=3`

Using the properties of logarithm, we get

`\log_3(18* 3)-\log_3x=3`
`\left[\because \log(ab)=\log a+\log b\right]`

`\log_3(54)-\log_3x=3`

`\log_3\left((54)/(x)\right)=3`
`\left[\because \log((a)/(b))=\log a-\log b\right]`

`(54)/(x)=3^3`
`[\because \log_ab=x\Leftrightarrow b=a^x]`

On further simplification, we get

`(54)/(x)=27`

`(54)/(27)=x`

`2=x`

Therefore, the value of x is 2.