Question

two group of hikers left camp at the same time and returned to the camp at the same time. one group hiked 6mph out to the camp and hiked back to the camp at 4mph. the second group hiked at constant speed all day. how fast did second group hike if each group hiked 24 mile

Answer 1

The second group of hikers hiked at a constant speed of 2.4 mph to cover the 24 miles distance in the same time it took the first group, who hiked out at 6 mph and back at 4 mph.

Step-by-step explanation:

First, let's find out how long it took for the first group of hikers to hike the 24 miles. Since they hiked 6mph out and 4mph back, we can calculate the time taken for each leg of the journey.

Time to hike out = distance/speed = 24 miles / 6 mph = 4 hours
Time to hike back = distance/speed = 24 miles / 4 mph = 6 hours
Total time taken for the first group = 4 hours + 6 hours = 10 hours.

Since the second group of hikers hiked at a constant speed and returned to the camp at the same time as the first group, they also took 10 hours to complete their 24 miles hike.

To find the constant speed of the second group: Speed = distance/time
Speed of second group = 24 miles / 10 hours = 2.4 mph.

Thus, the second group hiked at a constant speed of 2.4 mph to cover the same distance of 24 miles.