Question

Light with a wavelength of 500 nm (5. 10-7 m) is incident upon a double slit with a separation of 0.48 mm (4.80 10-4 m). A screen is located 2.4 m from the double slit. At what distance from the center of the screen will the second dark fringe beyond the center fringe appear?

Answer 1

The second dark fringe beyond the center fringe will appear at a distance of 3.6 µm from the center of the screen.

Step-by-step explanation:

To find the distance from the center of the screen to the second dark fringe, we can use the equation:

y = (m + 1/2) * λ * L / d

Where:

• y is the distance from the center of the screen
• m is the order of the fringe (in this case, it is 2)
• λ is the wavelength of light
• L is the distance between the double slit and the screen
• d is the separation between the slits

Plugging in the given values:

y = (2 + 1/2) * 500 nm * 2.4 m / 0.48 mm

y = 3/2 * 500 nm * 2.4 m / 0.48 mm

y = 3 * 500 nm * 2.4 m / 0.48 mm

y = 3600 nm * m / 0.48 mm

Converting the units:

y = 3.6 µm * m

Therefore, the second dark fringe beyond the center fringe will appear at a distance of 3.6 µm from the center of the screen.