Question

Can someone please help:)

1- A positive charge of 3x10-7 is located in a field of 27N/C directed toward the south. What is the force acting on the charge?



2- A positive test charge of 5x10-6Cis in an electric field that exerts a force of 2x10-4N on it.

What is the magnitude of the electric field at the location of the test charge?

Answer 1

Step-by-step explanation:

(1) Given that,

A charge,
`q=3* 10^(-7)\ C`

Electric field, E = 27 N/C

We need to find the force acting on the charge. The force on the charge is given by :

`F=qE\\\\F=3* 10^(-7)* 27\\F=8.1* 10^(-6)\ N`

So, the force acting on the charge is
`8.1* 10^(-6)\ N`

(b) Charge,
`q=5* 10^(-6)\ C`

Force,
`F=2* 10^(-4)\ N`

Let E be the electric field.

`E=(F)/(q)\\\\E=(2* 10^(-4))/(5* 10^(-6))\\\\E=40\ N/C`

So, the electric field is 40 N/C.