85.8k views
5 votes
(x^2+3x^2-kx-24)÷(x+3) what's the value of k??​

User Aliuk
by
7.7k points

1 Answer

7 votes

Answer:

-4

Explanation:

since x+3 is a factor of the polynomial (x^2+3x^2-kx-24), then;

x+3 = 0

x = -3

Substitute x = -3 into the polynomial

x^2+3x^2-kx-24 = 0

(-3)^2+3(-3)^2-(-3)k-24 = 0

9 + 27 + 3k - 24 = 0

36-24 + 3k = 0

12 = -3k

k = -12/3

k = -4

Hence the value of k is -4

User Guinaps
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories