Question

1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of the electric force? The constant k = 9 x 109 N-m2/C2

Solution:

Answer 1

F = 36 N

Step-by-step explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

`F=(kq_1q_2)/(r^2)\\\\F=(9* 10^9*8* 10^(-6)* 5* 10^(-6))/((0.1)^2)\\F=36\ N`

So, the magnitude of the electrostatic force is 36 N.