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What i an equation of the line that pae through the point (6,-4) perpendicular to the line 2x-y=5

User Tibalt
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1 Answer

12 votes
12 votes

Answer:

x +2y = -2

Explanation:

You want the line perpendicular to 2x-y = 5 that passes through (6, -4).

Perpendicular line

The slopes of perpendicular lines are opposite reciprocals. This means the equation of the perpendicular line can be formed by swapping the coefficients of x and y, and negating one of them. We want the leading coefficient to be positive, so we choose our line's equation to be ...

2x -y = constant . . . . . . . . . . original line

x +2y = <some constant>

The constant must be chosen so the equation is true at the given point:

x + 2y = (6) +2(-4) = -2

An equation for the perpendicular line is ...

x +2y = -2

What i an equation of the line that pae through the point (6,-4) perpendicular to-example-1
User Alex Chiang
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