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How tall is the cliff if the stone was initially traveling at -15.5 m/s and hits the ground 8.5 seconds later?

1 Answer

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Final answer:

The cliff is approximately 131.75 meters tall.

Step-by-step explanation:

To calculate the height of the cliff, we can use the kinematic equation:

h = yo + vyo*t + 0.5*ay*t^2,

Where h is the height of the cliff, yo is the initial height (0 in this case), vyo is the initial vertical velocity (-15.5 m/s), t is the time (8.5 seconds), and ay is the acceleration due to gravity (-9.8 m/s^2).

Substituting the values into the equation:

h = 0 + (-15.5) * 8.5 + 0.5 * (-9.8) * (8.5)^2,

h = -131.75 m.

Therefore, the cliff is approximately 131.75 meters tall.

User Jean Guzman
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