Question

Find the six first terms of an arithmetic sequence with:
d = 2
Po= 30

Answer 1

The first six terms of this arithmetic sequence are: 30, 32, 34, 36, 38, 40

Explanation:

The nth term of an arithmetic sequence is given by:

`P_n = P_0 + nd`

In which d is the common difference, that is, each term is increased by d.

d = 2, Po= 30

First term is 30, each consecutive is increased by 2. So

30, 32, 34, 36, 38, 40