Question

If the sum of 2 digits no. is 9 and their differenc is 1 find te no.​

Answer 1

Let the ten's digit no. be x and one's digit no. be y.

So the no. will be = 10x+y.

Given : x+y=9-----(I)

9(10x+y)=2(10y+x) ⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.

Explanation:

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