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A piece of tile weighs 300 g in air. If its density is 2.5 g/cc, what will be its weight in water (in grams)?

a. 200 g
b. 240 g
c. 260 g
d. 280 g

1 Answer

4 votes

Final answer:

To calculate the weight of the tile in water, we need to consider the concept of buoyancy. The weight of the tile in water would be less than 300 g. Based on the answer options, the closest option is (b) 240 g.

Step-by-step explanation:

To calculate the weight of the tile in water, we need to consider the concept of buoyancy. When an object is submerged in a fluid, it experiences an upward force known as buoyant force. This force is equal to the weight of the fluid displaced by the object.

The weight of the fluid displaced can be calculated using the formula:

Weight of fluid displaced = Density of fluid x Volume of fluid displaced

In this case, the density of water is 1 g/cc. The volume of fluid displaced by the tile is equal to its own volume. Therefore, we can calculate the weight of the tile in water as:

Weight in water = Weight in air - Weight of fluid displaced

Using the given values:

Weight in air = 300 g

Density of water = 1 g/cc

Volume of fluid displaced = Volume of the tile

Weight in water = 300 g - (1 g/cc x Volume of the tile)

Therefore, the weight of the tile in water would be less than 300 g. Based on the answer options, the closest option is (b) 240 g.

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