Question

Precalc! 50 points! please someone help me i’ll do anything for you

Answer 1

Explanation:

3. We know the x value which is -5 and the y value which is 1. We need to find the hypotenuse which we refer to the r. We use the pythagorean theorem for that

`{x}^(2) + {y}^(2) = {r}^(2)`

`{ - 5}^(2) + {1}^(2) = r {}^(2)`

`25 + 1 = r {}^(2)`

`26 = r {}^(2)`

`r = √(26)`

Now let find the sin, csc, and tan.

To find sin let use the formula

`(y)/(r)`

`(1)/( √(26) )`

Rationalize the denominator

`(1)/( √(26) ) * ( √(26) )/( √(26) ) = ( √(26) )/(26)`

`\sin = ( √(26) )/(26)`

To find cosecant, it is the reciprocal of sin so it would be

`\csc = (26)/( √(26) ) * ( √(26) )/( √(26) ) = √(26)`

To find tan, do

`(y)/(x)`

Which is simply

`\tan= (1)/( - 5)`

4. Kennedi is correct since in the 2nd quadrant

The x value is negative, and the y value is positive.

Since sin is referred in trig as the y value, sin must be positive.