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Question 6 (3 points) Q6. Suppose a network has 35 servers of which 7 fail. How many possibilities are there for the 7 that fail? Your Answer:

User Cragly
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1 Answer

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Final answer:

There are 3,747,166 possibilities for the 7 servers that fail in the network of 35 servers.

Step-by-step explanation:

The number of possibilities for the 7 servers that fail can be calculated using combinations.

Since there are 35 servers in total and 7 of them fail, we need to calculate the number of ways we can choose 7 servers from a set of 35. This can be done using the combination formula:

C(35, 7) = 35! / (7!(35-7)!)

= 35! / (7!28!) = (35 * 34 * 33 * 32 * 31 * 30 * 29) / (7 * 6 * 5 * 4 * 3 * 2 * 1)

= 3,747,166 possibilities

User Neto Buenrostro
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