Final answer:
When aniline is treated with different reagents, various chemical equations are involved. Br2 water reacts with aniline to produce C6H4BrN and HBr. CHCl3 and KOH react with aniline to yield C6H5NH, KCl, and H2O. HCl reacts with aniline to form C6H5NH3+ and Cl-.
Step-by-step explanation:
When aniline is treated with Br2 water, the following chemical equation is involved:
C6H5NH2 + Br2 + H2O → C6H4BrN + 2HBr
When aniline is treated with CHCl3 and KOH, the following chemical equation is involved:
C6H5NH2 + CHCl3 + KOH → C6H5NH + KCl + H2O
When aniline is treated with HCl, the following chemical equation is involved:
C6H5NH2 + HCl → C6H5NH3+ + Cl-