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The radius of a circular loop is 0.8 m. Against the current is 24 Amperes. The magnitude of the magnetic field at the center of the loop is: _______

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Final answer:

The magnitude of the magnetic field at the center of a circular loop with a radius of 0.8 m and a 24 A current is 6.0 x 10^-5 T.

Step-by-step explanation:

The magnitude of the magnetic field at the center of a circular loop of wire is given by the formula B = µ0I / (2R), where µ0 is the permeability of free space (µ0 = 4π x 10-7 T·m/A), I is the current through the loop, and R is the radius of the loop.

Plugging in the given values in the question, we get B = (4π x 10-7 T·m/A) x 24 A / (2 x 0.8 m). After calculating, the magnitude of the magnetic field at the center of the loop with a radius of 0.8 m and a current of 24 Amperes is 6.0 x 10-5 T (Tesla).

The magnetic field at the center of a circular loop can be calculated using the formula:

B = μ₀I/2R

Where B is the magnetic field, μ₀ is the permeability of free space (μ₀ = 4π×10-7 Tm/A), I is the current through the loop, and R is the radius of the loop.

Using the given values, we can plug them into the formula:

B = (4π×10-7 Tm/A) × (24 A) / (2 × 0.8 m)

Calculating this will give you the magnitude of the magnetic field at the center of the loop.

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