Final answer:
The magnitude of the magnetic field at the center of a circular loop with a radius of 0.8 m and a 24 A current is 6.0 x 10^-5 T.
Step-by-step explanation:
The magnitude of the magnetic field at the center of a circular loop of wire is given by the formula B = µ0I / (2R), where µ0 is the permeability of free space (µ0 = 4π x 10-7 T·m/A), I is the current through the loop, and R is the radius of the loop.
Plugging in the given values in the question, we get B = (4π x 10-7 T·m/A) x 24 A / (2 x 0.8 m). After calculating, the magnitude of the magnetic field at the center of the loop with a radius of 0.8 m and a current of 24 Amperes is 6.0 x 10-5 T (Tesla).
The magnetic field at the center of a circular loop can be calculated using the formula:
B = μ₀I/2R
Where B is the magnetic field, μ₀ is the permeability of free space (μ₀ = 4π×10-7 Tm/A), I is the current through the loop, and R is the radius of the loop.
Using the given values, we can plug them into the formula:
B = (4π×10-7 Tm/A) × (24 A) / (2 × 0.8 m)
Calculating this will give you the magnitude of the magnetic field at the center of the loop.