Final answer:
For any odd number n greater than 1, n(n^2-1) is divisible by 24 always.
Step-by-step explanation:
To determine if the expression n(n^2-1) is divisible by 24, let's factor it:
n(n^2-1) = n(n+1)(n-1)
Since n is an odd number, it can be expressed as 2k+1, where k is an integer. Substituting this value into the expression:
(2k+1)((2k+1)+1)((2k+1)-1) = (2k+1)(2k+2)(2k) = 24k(k+1)(k+1)
Therefore, for any odd number n greater than 1, n(n^2-1) is divisible by 24 always.