Question

What is the weight percentage of sulfuric acid in an aqueous solution which is 0.520 M in H₂SO₄? The density of the solution is 1.07 g/ml. [Atomic mass of S]

a) 9.2%
b) 10.0%
c) 11.2%
d) 12.5%

Answer 1

The weight percentage of sulfuric acid in the given aqueous solution is approximately 5.1%.

Step-by-step explanation:

The weight percentage of sulfuric acid in the aqueous solution can be calculated as follows:

First, calculate the molar mass of H₂SO₄: 2(1.0079 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.09 g/mol

Next, calculate the moles of H₂SO₄ present in 1000 g of the solution using its molarity: 0.520 mol/L x 1 L = 0.520 mol of H₂SO₄

Finally, calculate the weight of the H₂SO₄ in the solution: 0.520 mol x 98.09 g/mol = 51.03 g

To calculate the weight percentage, divide the weight of H₂SO₄ by the weight of the solution and multiply by 100%: (51.03 g / 1000 g) x 100% ≈ 5.1%

Therefore, the weight percentage of sulfuric acid in the aqueous solution is approximately 5.1%.