190k views
2 votes
How many different arrangements can be made by using all the letters of the word "equation" beginning with vowels and ending with consonants?

User Apouche
by
8.4k points

1 Answer

5 votes

Final Answer:

The number of different arrangements of the word "equation" that begin with vowels and end with consonants is 2880.

Step-by-step explanation:

The word "equation" has 8 letters: e, q, u, a, t, i, o, n.

There are 3 vowels (e, u, a) and 5 consonants (q, t, i, o, n).

To start with a vowel, there are 3 choices for the first letter.

To end with a consonant, there are 5 choices for the last letter.

The remaining 6 letters can be arranged in 6! (factorial) ways.

Multiply the choices for each position: 3 x 6! x 5 = 2880.

Therefore, there are 2880 different arrangements of the word "equation" that start with a vowel and end with a consonant.

User Kiratijuta
by
8.3k points