Final answer:
The number of half-lives that have occurred within 60 minutes cannot be determined with the provided half-life data. Without the correct half-life in appropriate units, we cannot calculate the exact volume of O2 collected after 60 minutes. The most accurate answer would be reached by obtaining the correct half-life information.
Step-by-step explanation:
The student is asking about the volume of O2 collected after 60 minutes from a first-order decomposition reaction involving hydrogen peroxide (H2O2). The half-life of this reaction is provided as 2.16 x 104 seconds.
First, we need to convert 60 minutes to seconds, as the half-life is given in seconds. There are 60 seconds in a minute, so 60 minutes is equivalent to 3600 seconds. Next, we determine the number of half-lives that have passed in 3600 seconds by dividing it by the half-life duration in seconds (3600 / 2.16 x 104). However, the problem in the question indicates that the reaction's half-life is not given in a standard format. Still, we can use the concept that after each half-life, half of the remaining reactant will be consumed, and consequently, half of the theoretical maximum volume of product will be produced.
Given a theoretical maximum volume of 100 mL of O2 and assuming we can use the half-life mechanism to predict the volume after 60 minutes, we can make an educated guess. If we assume the half-life to be considerably shorter than 3600 seconds (which we cannot determine from the provided data), the reaction will have gone through many half-lives within that duration, and thus, the volume of O2 collected after 60 minutes will approach 100 mL. However, without the exact half-life in the proper units, we cannot calculate the precise volume of O2 after 60 minutes.
Given the incomplete data, we cannot choose an exact answer from the provided options, and the student should be encouraged to seek clarification or the correct half-life value to solve the problem accurately.