Question

If a hollow spherical ball rolls on a table without slipping, the percentage of its total kinetic energy associated with rotation is:

(a) 30%
(b) 40%
(c) 50%
(d) 60%

Answer 1

When a hollow spherical ball rolls on a table without slipping, the percentage of its total kinetic energy associated with rotation is 40%.

Step-by-step explanation:

When a hollow spherical ball rolls on a table without slipping, the percentage of its total kinetic energy associated with rotation can be calculated using the formula:

K rotational = (2/5)(I/M)(v^2)

where K rotational is the kinetic energy associated with rotation, I is the moment of inertia of the hollow sphere, M is the mass of the hollow sphere, and v is the linear velocity of the hollow sphere. The moment of inertia for a hollow sphere is given by I = (2/3)MR^2, where R is the radius of the hollow sphere.

Substituting the given values and simplifying, we find that the percentage of the total kinetic energy associated with rotation is 40%.