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A projectile is fired from O(0,0,0) with an initial speed v. What will be the speed at an altitude h from the ground?

User Jevgenij
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Final answer:

The speed at altitude h is determined by the initial speed v and the loss in potential energy due to height h using the conservation of energy principle.

Step-by-step explanation:

The speed at altitude h from the ground for a projectile fired from the origin would depend on its initial speed v and the energy lost due to gravitational potential energy at height h.

The horizontal component of the velocity Ux remains constant since no external horizontal forces are acting on the projectile (neglecting air resistance). However, the vertical velocity component will change due to gravity. If the projectile is only affected by gravity, its speed at height h can be determined by using the principles of conservation of energy.

The total kinetic energy plus potential energy at any point during its flight will be equal to the total initial kinetic energy. Assuming no air resistance, speed at altitude h will be given by the equation v = sqrt(v_0^2 - 2gh), where v_0 is the initial velocity, g is the acceleration due to gravity, and h is the altitude.

User Beerbajay
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