89.8k views
2 votes
A particle performs SHM with a period T and amplitude A. The mean velocity of the particle over the time interval during which it travels a distance A/2 from the extreme position is

a) 0
b) A/2
c) A/4
d) A

1 Answer

7 votes

Final answer:

The mean velocity of a particle over the time interval during which it travels a distance A/2 from the extreme position is A/2. Therefore, the correct answer is b) A/2.

Step-by-step explanation:

In simple harmonic motion (SHM), the mean velocity of a particle over the time interval during which it travels a distance A/2 from the extreme position is A/2.

To understand this, consider that the particle oscillates between the extreme positions of +A and -A. When it reaches the midpoint of its oscillation at A/2, it momentarily stops and changes direction.

This means that the average velocity over the time it takes to cover a distance of A/2 is zero. Therefore, the mean velocity over this time interval is A/2.

Simple harmonic motion (SHM) is a repetitive back-and-forth movement or oscillation exhibited by certain systems under the influence of a restoring force that is directly proportional to the displacement from an equilibrium position and acts in the opposite direction.

User Dng
by
8.0k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.