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An automobile moving at a velocity of 40 km/hr is experiencing a wind resistance of 2 kN. If the automobile is moving at a velocity of 50 km/hr, the power required to overcome the wind resistance is: _________

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Final answer:

The power required to overcome wind resistance when the automobile is moving at a velocity of 50 km/hr is P≈62.83kW

Step-by-step explanation:

The power (P) required to overcome wind resistance can be calculated using the formula:

P = F × v

where F is the force of wind resistance and v is the velocity of the automobile.

Given that the wind resistance (F) is 2 kN and the velocity (v) is changing from 40 km/hr to 50 km/hr, we can convert the velocities to meters per second (m/s) by multiplying by 1000/3600 (Since 1km/hr= 1000/3600 m/s).

At 40 km/hr:

v1= 40×1000/3600 = 11.11m/s

At 50 km/hr:

v2 = 50×1000/3600 = 13.89m/s

Now, substitute these values into the power formula:

P = F × (v2-v1)

P = (2000N)⋅(13.89m/s−11.11m/s)

P≈62.83kW

The power required to overcome wind resistance when the automobile is moving at a velocity of 50 km/hr is approximately 62.83kW. This calculation is based on the relationship between power, force, and velocity.

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