Final answer:
To increase the car's velocity from 18 km/hr to 36 km/hr, the work done is calculated using the work-energy principle, resulting in 56250 Joules required.
Step-by-step explanation:
The work to be done to increase the velocity of a 1500 kg car from 18 km/hr to 36 km/hr can be calculated using the work-energy principle. This principle states that work done on an object is equal to the change in its kinetic energy.
First, we need to convert the velocities from km/hr to m/s by multiplying with a factor of 5/18. So, the initial velocity (v1) is 5 m/s and the final velocity (v2) is 10 m/s. The work done (W) is given by:
W = ∆KE = ½ m(v2^2 - v1^2)
Substituting the values:
W = 0.5 × 1500 kg × (10^2 m^2/s^2 - 5^2 m^2/s^2)
W = 0.5 × 1500 kg × (100 m^2/s^2 - 25 m^2/s^2)
W = 0.5 × 1500 kg × 75 m^2/s^2
W = 56250 J
Therefore, the work to be done to increase the velocity of the car is 56250 Joules.