Final answer:
The number of ways a man can be dealt 26 cards without getting two cards of the same suit and denomination is 4 * C(48, 5).
Step-by-step explanation:
To find the number of ways in which a man can be dealt 26 cards so that he does not get two cards of the same suit and same denomination, we need to consider the different possibilities for the combinations of suits and denominations.
There are 4 suits (clubs, diamonds, hearts, spades) and each suit has 13 cards (A, 2, 3, ..., 10, J, Q, K). We want to select 26 cards such that no two cards have the same suit and denomination.
To solve this problem, we can think of it as selecting one card from each suit, which gives us 4 choices. Then, we need to choose 5 more cards from the remaining 48 cards without any restrictions. This can be done in C(48, 5) ways. Therefore, the total number of ways to deal 26 cards without getting two cards of the same suit and same denomination is 4 * C(48, 5) 5