Question

A coil of area 5 cm^2 and having 20 turns is placed in a uniform magnetic field of 103 Gauss. The normal to the plane of the coil makes an angle of 60° with the magnetic field. The flux in Maxwell through the coil is:

(a) 1.5 mWb
(b) 2.0 mWb
(c) 2.5 mWb
(d) 3.0 mWb

Answer 1

The magnetic flux through the coil with the given parameters is 1.5 mWb. This is calculated using the magnetic flux formula with the provided values for the area, number of turns, magnetic field, and angle, selecting the correct answer (a) 1.5 mWb.

Step-by-step explanation:

To calculate the magnetic flux through a coil of wire in a magnetic field, we use the formula:

Φ = B * A * cos(θ)

Here, Φ is the magnetic flux in Webers (Wb), B is the magnetic field strength in Teslas (T), A is the area of the coil in square meters (m²), and θ is the angle between the normal to the coil and the magnetic field.

Given:

Thus, the total flux through the coil is calculated as:

Φ = N * B * A * cos(θ)

Φ = 20 * 103 * 10⁻´ T * 5 * 10⁻´ m² * cos(60°)

Φ = 20 * 103 * 5 * cos(60°) * 10⁻¸ Wb

Φ = 20 * 103 * 2.5 * 0.5 * 10⁻¸

Φ = 1.5 * 10⁻´ Wb = 1.5 mWb

Therefore, the correct answer is (a) 1.5 mWb.

The magnetic flux through a coil would be at its maximum when the angle between the normal to the plane of the coil and the magnetic field is 0°.