Question

Give the following code, where x = ), what is the resulting value of x after the for-loop terminates?

for (int i = 0; i < 5; i++)
x =+ 1;
A) 4
B) 10
C) 0
D) 15
E) 5

Answer 1

The resulting value of x after the for-loop, assuming the proper increment operator '+=', is 5. The loop increases x's value by 1 with each iteration, for a total of 5 iterations.

Step-by-step explanation:

The code provided contains a typo with the assignment operator. The correct operator should be '+=' and not '=+'. Assuming the correct operator was used, each iteration of the loop increments the value of x by 1. Given that x starts at 0 (assuming the symbol for 'x' is a typo and should represent the initial value), and the loop runs 5 times, x would be incremented 5 times.

Therefore, after the for-loop terminates, the value of x would be:

• x = 0 + 1 + 1 + 1 + 1 + 1
• x = 5

Hence, the correct answer is E) 5.