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1 vote
What would be printed out after the following code:

String name = "Anthony Rizzo";
System.out.printIn(name.charAt(5));
A) H
B) O
C) N
D) Y

User Neha Gupta
by
8.6k points

1 Answer

3 votes

Final answer:

The code will print out the character 'n' from the String "Anthony Rizzo", as it is located at index 5 (the sixth position).

Step-by-step explanation:

The code provided uses the charAt method to access a character at a specific index in a String object in Java. The String "Anthony Rizzo" is being accessed at index 5, which in Java is the sixth character because indices are zero-based. Therefore, the character at index 5 is 'n', since counting starts from 0 (A=0, n=1, t=2, h=3, o=4, n=5). Hence, the output of the code would be the letter 'N' if printed literally or 'n' if we consider case-sensitivity.

User Sfgroups
by
8.4k points