Question

What is the output of the following code fragment:

int x = 50;
int y + 25;
do {
x +=y
} while ( x < 0);
System.out.printIn(x);
A) 2
B) 25
C) 50
D) 75

Answer 1

The corrected code fragment does not execute the loop because the condition is false from the start; hence, the output will be the initial value of x, which is 50.

Step-by-step explanation:

The provided code fragment contains multiple errors, making it impossible to determine an accurate output. However, if we correct the errors and assume the intention was to have a working do-while loop, we can analyze a corrected version of the code.

Firstly, the variable y is declared incorrectly with a '+' rather than '='. It should be initialized as int y = 25;. Also, the statement x += y is missing a semicolon at the end, and the System.out.printIn should be System.out.println. The correct code would therefore look like this:

int x = 50;
int y = 25;
do {
x += y;
} while ( x < 0 );
System.out.println(x);

After these corrections, the loop will not execute because the condition x < 0 is false from the start (x is 50). Thus, the output will be the initial value of x, which is 50.