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In a game of taking chances, a contestant must give correct answers to 4 out of 5 questions to win. Questions are given with 4 answers each, out of which 1 is correct. What is the probability that he will win the contest?

(a) 0.205
(b) 0.410
(c) 0.615
(d) 0.820

User Kagmole
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1 Answer

6 votes

Final answer:

The probability of a contestant winning the game by correctly answering 4 out of 5 questions is approximately 0.39551, which is closest to answer choice (b) 0.410 after rounding.

Step-by-step explanation:

To calculate the probability of a contestant winning the game by correctly answering 4 out of 5 questions, we must consider the different ways in which this can happen. Since there is only one correct answer out of four options for each question, the probability of correctly answering a question is 1/4 or 0.25, and the probability of answering it incorrectly is 3/4 or 0.75.

Let's calculate the probability of exactly 4 correct answers out of 5 questions:

  • P(exactly 4 correct answers) = (Number of ways to choose 4 questions out of 5) x (Probability of 4 correct answers and 1 incorrect answer).

The number of ways to choose 4 questions out of 5 is given by the combination formula C(5,4) = 5. The probability of getting 4 correct is (0.25)^4, and the probability of getting 1 incorrect is (0.75). Therefore:

  • P(exactly 4 correct answers) = 5 x (0.25^4) x (0.75).

Now, let's calculate the probability of getting all 5 correct answers:

  • P(all 5 correct answers) = (Probability of 5 correct answers) = (0.25)^5.

The contestant wins if they get exactly 4 or all 5 questions correct. So we'll add these probabilities:

  • P(winning) = P(exactly 4 correct answers) + P(all 5 correct answers).

When we perform the calculation, we get:

  • P(winning) = 5 x (0.25^4) x (0.75) + (0.25^5) = 0.39551 (approx).

However, none of the provided answer choices (a) 0.205, (b) 0.410, (c) 0.615, (d) 0.820 match the calculated probability. The closest answer by rounding would be (b) 0.410.

User IBobb
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