Question

An R-410A heat pump operating in the cooling mode has a suction pressure of 118 psig. Adding 2 psig for pressure drop in the coil, the true outlet pressure is 120.5 psig. The temperature of the suction line at the outlet of the evaporator is 53°F. What is the superheat?

a) 5°F
b) 10°F
c) 15°F
d) 20°F

Answer 1

To find the superheat, subtract the saturation temperature from the actual temperature of the suction line outlet.

Step-by-step explanation:

To find the superheat, we need to subtract the saturation temperature from the actual temperature of the suction line outlet.

First, let's convert the given pressure from psig to psia by adding 14.7 psi to the suction pressure: 118 psi + 14.7 psi = 132.7 psia.

Next, we need to find the saturation temperature for the given pressure using a temperature-pressure chart for R-410A. Let's assume that the saturation temperature is 50°F.

Finally, we can calculate the superheat by subtracting the saturation temperature from the actual temperature: 53°F - 50°F = 3°F.