Final answer:
The probability of receiving exactly two calls in a 5-minute interval, given a rate of 48 calls per hour, is calculated using the Poisson probability formula and is determined to be approximately 14.65%.
Step-by-step explanation:
To calculate the probability of receiving exactly two calls in a 5-minute interval at a reservation desk where calls arrive at the rate of 48 per hour, we can use the Poisson distribution formula, which is suitable for finding probabilities of a number of events happening in a fixed interval of time when these events occur with a known constant rate and independently of the time since the last event.
The formula for the Poisson probability is P(X=k) = (e-λ*λk)/k!, where λ is the average number of events in the interval, and k is the number of events for which we want to find the probability.
Here, λ for a 5-minute interval is (48 calls/hour) * (1 hour/60 minutes) * 5 minutes = 4 calls/5 minutes.
Thus, P(X=2) = e-4*42/2! = (0.0183)*16/2 = 0.1465 or 14.65%.