Final answer:
The question deals with the expansion of car radiator fluid due to an increase in temperature from 10.0°C to 95.0°C. The initial volume of 16.0 liters expands with a given coefficient of expansion (400×10-6/°C), resulting in an overflow volume that can be calculated using a simple formula involving the coefficient, initial volume, and change in temperature.
Step-by-step explanation:
The question concerns the expansion of a car radiator fluid when heated from 10.0°C to 95.0°C. The initial volume of the radiator fluid is 16.0 liters, and the coefficient of volume expansion (β) for the fluid is given as 400×10-6/°C. We can calculate the change in volume (ΔV) of the radiator fluid using the formula:
ΔV = β × V0 × ΔT
Where V0 is the initial volume, β is the coefficient of volume expansion, and ΔT is the change in temperature. In this case, ΔT = 95.0°C - 10.0°C = 85.0°C. Inserting the given values into the equation:
ΔV = (400×10-6/°C) × 16.0 L × 85.0°C
This calculation will give us the volume that has overflowed. Note that the actual operating temperatures of car radiators can be higher than 95.0°C, and thus the volume overflow could potentially be greater than calculated with the given coefficient of expansion.