The value of SV is square root of 65.
In a right-angled triangle STU with TV as the perpendicular bisector, we can use the Pythagorean Theorem to find the length of SV:
The Pythagorean Theorem is given by
![\[ a^2 + b^2 = c^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ztlj7w2crnu8irtu4w20tft65vmrapasq9.png)
where a and b are the legs of the right-angled triangle, and c is the hypotenuse.
In this case, ST and SU are the legs, and SV is the hypotenuse.
![\[ ST^2 + SU^2 = SV^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/cw62f58q021yeysywm2fczbzvonx420pq3.png)
Substitute the given values:
![\[ 4^2 + 7^2 = SV^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/ift1ekxjox2sr5apr6tkg7icy9ipcpbdpj.png)
![\[ 16 + 49 = SV^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/fd9vpeae0cdbio88gwa4gxe75qp78f0j6v.png)
![\[ 65 = SV^2 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/9l5qdiovut248jwo2bddle334wpcxpxpxe.png)
![\[ SV = √(65) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/lt7xgis0l0x4wxv5try31kjsjyp8rbmsa5.png)
Therefore, SV is the square root of 65.