Question

Given the following balanced equation, how many moles of O2 would be produced by 3.4 moles of Ag2O?

2 AG2O → 4 AG + O2

Answer 1

1.7 moles of O2 would be produced by reacting 3.4 moles of Ag2O, as determined from the stoichiometry of the balanced equation 2 Ag2O → 4 Ag + O2.

Step-by-step explanation:

To determine how many moles of O2 would be produced by 3.4 moles of Ag2O using the balanced equation 2 Ag2O → 4 Ag + O2, we look at the stoichiometry of the reaction.

The balanced equation indicates that 2 moles of Ag2O produce 1 mole of O2.

Therefore, we can set up a direct proportion to find the moles of O2 produced from 3.4 moles of Ag2O:

(2 moles Ag2O / 1 mole O2) = (3.4 moles Ag2O / x moles O2)
Solving for x, we find that:
x = (3.4 moles Ag2O) × (1 mole O2 / 2 moles Ag2O)
x = 1.7 moles O2
The answer is that 1.7 moles of O2 would be produced by reacting 3.4 moles of Ag2O.