The value of K for the reaction N2 + 3H2 = 2NH3 at 555.0K is approximately 5.15 × 10^29.
Step-by-step explanation:
The reaction provided is:
N2 + 3H2 → 2NH3
Given the standard free energy of formation of ammonia, which is -16.5 kJ/mol, we can calculate the equilibrium constant, K, at 555.0K using the formula:
ΔG = -RT ln(K)
Where ΔG is the standard free energy change, R is the gas constant, and T is the temperature in Kelvin. By rearranging the formula, we get:
K = e^(−ΔG/RT)
Plugging in the given values, we get:
K = e^(−(−16.5×10^3 J/mol)/(8.314 J/(mol·K) × 555.0 K)) = 5.15 × 10^29
Therefore, the value of K for the reaction at 555.0K is approximately 5.15 × 10^29.